# ? Find¶

Find the first occurrence of an item in a list.

x?y   ?[x;y]

where x is a list or a null, returns for

• atom y the smallest index of y
• list y the smallest index of each item of y

Where y or an item of it is not found in x, the smallest index is the smallest integer not found in key x, i.e. count x. Comparisons are exact and are not subject to to comparison tolerance.

q)w:10 -8 3 5 -1 2 3
q)w?-8
1
q)w[1]
-8
q)w?3              / the first occurrence of 3
2
7
q)w[7]
0N
q)"abcde"?"d"
3

?(find) is a multithreaded primitive.

## Type-specific¶

Find is type-specific relative to x. Where x is a

• simple list and y a list whose atoms are all the same type as x, and whose first item is a list, the result corresponds to y item-by-item; i.e. Find is right-atomic.

q)rt:(10 5 -1;-8;3 17)
q)i:w?rt
q)i
0 3 4
7
2 7
q)w[i]
10 5 -1
0N
3 0N

(If the first item of y is an atom, a type error is signalled.)

• list of lists and y is a simple list, items of x are matched with the whole of y.

q)u:("abcde";10 2 -6;(2 3;ab))
q)u?10 2 -6
1
q)u?"abcde"
0
• list of lists and y is a mixed list then items of x are matched with items of y.

q)u?(2 3;ab)
3 3

In this case Find matches items of x with 2 3 and ab , not (2 3;ab).

The rank of y should match the rank of the list element for x.

## Rank-sensitive¶

x?y canâ€™t deal with mixed-rank x. If rank x is n then x?y looks for objects of rank n-1.

2 3?2 3#til 6  / looks for rank 0 objects
(0 1 2;4 5)?2 3#til 6 / looks for rank 1 objects

A solution to find (2 3;ab) is

q)f:{where x~\:y}
q)f[u;(2 3;ab)]
,2

## Searching tables¶

Where x is a table then y must be a compatible record (dictionary or list) or table. That is, each column of x, paired with the corresponding item of y, must be valid arguments of Find.

q)\l sp.q
q)sp?(s1;p4;200)
3
q)sp?spqty!(s2;p5;450)
12

## Implicit Find¶

Find is implicit in the definitions of except, in, within` and dictionary lookup.