# ' Compose¶

Compose a unary value with another

'[f;ff][x;y;z;…]

Where

• f is a unary value
• ff is a value rank ≥1

the derived function '[f;ff] has the rank of ff and returns f ff[x;y;z;…].

q)ff:{[w;x;y;z]w+x+y+z}
q)f:{2*x}
q)d:('[f;ff])               / Use noun syntax to assign a composition
q)d[1;2;3;4]                / f ff[1;2;3;4]
20
q)'[f;ff][1;2;3;4]
20

Extend Compose with Over / or over to compose a list of functions. Use

• '[;] to resolve the overloads on '
• noun syntax to pass the composition as an argument to over
q)g:10*
q)dd:('[;]) over (g;f;ff)
q)dd[1;2;3;4]
200
q)(('[;])over (g;f;ff))[1;2;3;4]
200
q)'[;]/[(g;f;ff)][1;2;3;4]
200

## Implicit composition¶

Compose one or more unary values with a higher-rank value

Values can be composed by juxtaposition within parentheses.

The general form is a sequence of unaries f, g, h… terminating with a value ff of rank ≥2. The rank of (f g h… ff) is the rank of ff.

q)x:-100 2 3 4 -100 6 7 8 9 -100
q)(x;0 (0|+)\x)
-100 2 3 4 -100 6 7  8  9  -100
0    2 5 9 0    6 13 21 30 0

Above, (0|+) composes the unary projection 0| with Add. The composition becomes the argument to Scan, which derives the ambivalent function (0|+)\, which is then applied infix to 0 and x to return cumulative sums.

If we take -100 to flag parts of x, the expression max 0 (0|+)\x returns the largest of the sums of the parts.

To compose a sequence of unary values, use Apply or Apply At.